What combination of resistors can I use to get 11 8 ohms?
you would use a series of 10 ohms + 1.8 ohms to get 11.8 ohms.
sorry i had to edit i put k because of being so drunk.
we really need more information, for example at 11.8
the simple is to serialize resistors of 10 and 2 ohms. it will be 12 ohms, which is close enough for most purposes. if you want to use a more accurate resistor, put a 720 ohm resistor in parallel with both, which brings you back to 11.801379310344828 ohms. you can make a 713 with a resistance of 680 and 33 ohms in series.
you can get 11.88 with a resistance of 1 ohm, a 10 ohm and four resistors of 2.2 ohms in series. the color codes would be a black-brown black, a black-brown yellow, and four white-red resistors. or replace the four 0.22 ohm resistors with a 1.8 ohm resistor, yellow gray brown color code.
or you can use a compound ground potentiometer and measure its resistance with a multimeter when dialing for accuracy. (probably easier, cheaper and faster)
how far do you need it? After all, the resistors are not repaired, they fall within tolerances and change a little in time and temperature.
I can put in series a group of resistors whose book value will be exactly 11,80000 ohms, but if they are all at 1%, the result will be only 11,8 +/- 1%.
for recording. The value 118 corresponds to a real decade value e96 of i96, which means that you can obtain a single standard resistor of 11.8 ohm +/- 1% in a number of power sizes, from any supplier of electronic appliances.
it remains subject to thermal and temporal drift.
If you need 11,800 ohms exactly, you can get a low temperature resistance of 10 ohms and a potentiometer five or twenty-five turns in series and adjust the potentiometer until you get exactly where you want with a setting very precise.
It will also be subject to drifting weather and temperature. This is where the technical skills as an engineer come into play to minimize these drifts.
